What if Ron Paul wins Iowa? - CSMonitor.com - Amanda Paulson:
Dec. 19, 2011 - "According to the latest Iowa survey of the Republican presidential field, Rep. Ron Paul of Texas is now on top, with 23 percent of likely caucusgoers supporting him. The Public Policy Polling survey puts former Massachusetts Gov. Mitt Romney second (20 percent) and a rapidly falling Newt Gingrich third (14 percent).
"A second poll released Monday also has Congressman Paul leading Mr. Romney, 24 to 18 percent.... And New York Times polling analyst Nate Silver, who has developed his own forecasting model, is predicting a Paul victory in Iowa. That model – which takes various polls into consideration, and weighs them according to accuracy and other factors – now gives Paul a 52 percent chance of an Iowa victory. It assigns Romney a 28 percent chance of winning, and Gingrich an 8 percent chance."
Read more: http://www.csmonitor.com/USA/Politics/The-Vote/2011/1219/What-if-Ron-Paul-wins-Iowa
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Dec. 19, 2011 - "According to the latest Iowa survey of the Republican presidential field, Rep. Ron Paul of Texas is now on top, with 23 percent of likely caucusgoers supporting him. The Public Policy Polling survey puts former Massachusetts Gov. Mitt Romney second (20 percent) and a rapidly falling Newt Gingrich third (14 percent).
"A second poll released Monday also has Congressman Paul leading Mr. Romney, 24 to 18 percent.... And New York Times polling analyst Nate Silver, who has developed his own forecasting model, is predicting a Paul victory in Iowa. That model – which takes various polls into consideration, and weighs them according to accuracy and other factors – now gives Paul a 52 percent chance of an Iowa victory. It assigns Romney a 28 percent chance of winning, and Gingrich an 8 percent chance."
Read more: http://www.csmonitor.com/USA/Politics/The-Vote/2011/1219/What-if-Ron-Paul-wins-Iowa
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